Question 866315
{{{3^(-5)*3^2*4^2=3^(-5+2)*16}}}
{{{3^(-5)*3^2*4^2=3^(-3)*16}}}
{{{3^(-5)*3^2*4^2=(1/3^(3))*16}}}
{{{3^(-5)*3^2*4^2=(1/27)*16}}}
{{{3^(-5)*3^2*4^2=16/27}}}