Question 866141
{{{y<=x^2+2x-8}}}


Complete the square to put into standard form.
{{{y<=x^2+2x+1-1-8}}}
{{{y<=(x+1)^2-9}}}


The vertex of this which will be included with the graph is (-1,-9).  The region of the plane to be included in the solution will be the parabola and all points below the parabola.


{{{graph(300,300,-7,7,-12,8,y<=x^2+2x-8)}}}