Question 865865
Not sure how you got from line 3 to line 4.
{{{t^2-3t-4>0}}}
{{{(t-4)(t+1)>0}}}
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{{{graph(300,300,-5,5,-5,5,(x-4)(x+1))}}}
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{{{t-4>0}}} and {{{t+1<0}}}
{{{t>4}}} and {{{t<-1}}}
{{{e^x>4}}} and {{{e^x<-1}}}
The second solution is not possible so we discard it.
{{{e^x>4}}}
{{{x>ln(4)}}}