Question 846312
{{{y=(2x-1)/(x-3)}}}

{{{y(x-3)=(x-3)(2x-1)/(x-3)}}}

{{{xy-3y=2x-1}}}

{{{xy-2x=3y-1}}}

{{{x(y-2)=3y-1}}}


{{{x=(3y-1)/(y-2)}}}

so the inverse function is:


{{{g(x)=(3x-1)/(x-2)}}}