Question 865839
Change the base-four logs into base-two logs, using Change Of Base formula.


{{{log(2,1)-(log(2,x))/(log(2,4))+(log(2,y))/(log(2,4))=2}}}
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As a side step, {{{log(2,4)=log(2,2^2)=2*log(2,2)=2*1=2}}}
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{{{0-log(2,x)/2+log(2,y)/2=2}}}
{{{-log(2,x)/2=2-log(2,y)/2}}}
{{{log(2,x)/2=log(2,y)/2-2}}}
{{{log(2,x)=log(2,y)-4}}}
{{{log(2,x)-log(2,y)=-4}}}
{{{log(2,y)-log(2,x)=4}}},  multiplied both sides by negative 1
{{{log(2,y/x)=4}}}
Put into expon. form.

{{{2^4=y/x}}}
{{{x*2^4=y}}}
{{{x=y/2^4}}}
{{{highlight(x=y/16)}}}



------------not the best form----
{{{x=2^(((log(2,y))-4))}}}