Question 865825
x+y=50 and xy=16x, but the area description in words is strange.


Solve the sum equation for y and substitute into the area equation.
{{{x(50-x)=16x}}}
{{{-x^2+50x-16x=0}}}
{{{x^2-50x+16x=0}}}
{{{x^2-34x=0}}}
{{{x(x-34)=0}}}
{{{highlight(x=34)}}}.