Question 865749
Put into standard form according to what is given:
{{{highlight_green(y=a(x-3)^2-4)}}}, and a sketch or picture or visualization using the two given points will suggest the vertex is a minimum, so {{{a>0}}}.


{{{a(x-3)^2=y+4}}}
{{{a=(y+4)/(x-3)^2}}}
Substitute the given point to be contained.
{{{a=(-2+4)/(2-3)^2}}}
{{{highlight_green(a=2)}}}.