Question 72926
{{{ ((6 p - 1 8)/(9 p))/((3 p - 9)/(p ^ 2 +  2 p)) }}}
Before you begin factoring remember the following:
{{{ (a/b)/(c/d) = ad/bc }}}
Apply this to your problem
{{{ ((6p-18)(p^2+2p))/((9p)(3p-9)) }}}
Now factor
{{{ (6p(p-3)(p+2))/((27p)(p-3)) }}}
Cancel the (p-3)
{{{ (6p(p+2))/(27p) }}}
reduce the 6p and the 27p by dividing by 3
{{{ (2(p+2))/(9) }}}
This is your final answer