Question 865522
Use logarithms to solve the equation {{{5^x = 2^(2x+1)}}}
the log equiv of exponents
{{{xlog(5) = (2x+1)log((2)))}}}
find the log of  5 and 2
.699x = .301(2x+1)
.699x = .602x + .301
.699x - .602x = .301
.097x = .301
x = {{{.301/.097}}}
x = 3.103