<PRE><B>Question 865478</B>
H and M traveled on the same route to Town X. H left his house at 6.15am and traveled at an average speed of 80 km/h. 45 minutes later, M left for Town X and traveled at an average speed of 100km/h . At what time did they meet on the way ?
Answer
 distance traveled in 45 minutes by H( As M left 45 minutes later)
 = 80 x 45/60= 60 km 
M left house at 7 am( 45 minutes later than H ) by the time H traveled  60 KM  with 
speed of M is 100 km/H 
time taken to meet H with difference of 60 km . means M have to traveled 60 km to meet H
time=distance/ speed
     = 60/100  hours = 0.6 hours = 0.6 x 60  =36 minutes                          ( we know 1 hours is equal to 60 minutes )
therefor both will meet after 36 minutes after starting of M 
Both will meet at 07:36 
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