Question 865485
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Hi
parabola: x^2-8y+24=0   0r = {{{(1/8)x^2 - 3 = y}}} 1/4p = 1/8,  p = 2
{{{drawing(300,300,   -10,10,-10,10,  
 grid(1),
circle(0,-3,0.4),
circle(0,-1,0.4),
graph( 300, 300, -10,10,-10,10,0,-5,(1/8)x^2 -3))}}}