Question 865271
 the band members sold tickets to their concert performance. some were $3 tickets and some were $8 tickets. there were 10 more than twice as many $8 tickets sold as $3 tickets. the total sales were $1,448. how many tickets of each price were sold. 

$3 tickets ----------------------x
$8 tickets ----------------------y

y=2x+10
y-2x=10.................(1)

3x+8y=1448...............(2)

solve for x & y

-2	x	+	1	y	=	10	.............1	
Total value								
3	x	+	8	y	=	1448	.............2	
Eliminate	y							
multiply (1)by		-8						
Multiply (2) by		1						
16	x		-8	y	=	-80		
3	x	+	8	y	=	1448		
Add the two equations								
19	x				=	1368		
/	19							
x	=	72						
plug value of			x	in (1)				
-2	x	+	1	y	=	10		
-144		+		y	=	10		
				y	=	10	+	144
				y	=	154		
				y	=	154		
x=	72		number of	$3				
y=	154		number of	$8				
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