Question 865141
w width
L length
{{{L=w+8}}}
{{{wL=28=w(w+8)}}}
{{{w^2+8w-28=0}}}---------Not factorable.  Use the general solution to a quadratic equation to find w.


{{{w=(-8+sqrt(64+4*28))/2}}}
{{{w=(-8+sqrt(176))/2}}}
{{{w=(-8+sqrt(2*8*11))/2}}}
{{{w=(-8+4*sqrt(11))/2}}}
{{{highlight(w=-4+2sqrt(11))}}}-------and use this yourself to find L according to {{{L=w+8}}}.