Question 865126
xy=24 and 2(x+y)=68


{{{x+y=34}}} and {{{xy=24}}}.
{{{y=34-x}}} substituted into simplified area equation gives:
{{{x*(34-x)=24}}}
{{{34x-x^2-24=0}}}
{{{x^2-34x+24=0}}}
{{{x=(34+sqrt(34^2-4*24))/2=(34+sqrt(1060))/2=(34+sqrt(20*53))/2}}}
{{{x=(34+2*sqrt(5*53))/2=17+sqrt(265)}}}
{{{highlight(x=17+sqrt(265))}}}
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{{{y=34-x=34-17-sqrt(265)=17-sqrt(265)}}}
{{{highlight(y=17-sqrt(265))}}}------and this will work because sqrt(265)=16.28 approximately.