Question 865097
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<pre><b>

<font color="red">&#9856;&#9856;   &#9856;&#9857;</font><font color="blue">   &#9856;&#9858;   &#9856;&#9859;   &#9856;&#9860;   &#9856;&#9861;</font>

<font color="red">&#9857;&#9856;</font><font color="blue">   &#9857;&#9857;   &#9857;&#9858;   &#9857;&#9859;   &#9857;&#9860;   &#9857;&#9861;

&#9858;&#9856;   &#9858;&#9857;   &#9858;&#9858;   &#9858;&#9859;   &#9858;&#9860;   &#9858;&#9861;

&#9859;&#9856;   &#9859;&#9857;   &#9859;&#9858;   &#9859;&#9859;   &#9859;&#9860;   &#9859;&#9861;

&#9860;&#9856;   &#9860;&#9857;   &#9860;&#9858;   &#9860;&#9859;   &#9860;&#9860;   &#9860;&#9861;

&#9861;&#9856;   &#9861;&#9857;   &#9861;&#9858;   &#9861;&#9859;   &#9861;&#9860;   &#9861;&#9861;</font></font>

The <font color="red">red</font> dice rolls ARE less than 4.
  
The <font color="blue">blue</font> ones are NOT less than 4.

Since it's odds AGAINST, count the <font color="blue">blue</font> ones first.

There are <font color="blue">33</font> of them. So we write that number first

<font color="blue">33</font>

Then after the <font color="blue">33</font> we put either a colon ":" or else the word "to".

<font color="blue">33</font>:   or  <font color="blue">33</font> to

Next we count the <font color="red">red</font> ones.

There are <font color="red">3</font> of them.  So we write the number <font color="red">3</font> after the colon or the
word "to":

<font color="blue">33</font>:<font color="red">3</font>   or  <font color="blue">33</font> to <font color="red">3</font>.

Now since you can divide both the <font color="blue">33</font> and the <font color="red">3</font> by 3, you can write those
as

<font color="blue">11</font>:<font color="red">1</font>   or  <font color="blue">11</font> to <font color="red">1</font>.

Edwin</pre></b>