Question 864987
{{{x^2-3x-28=0}}}
Use the Quadratic Formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
Plug in the values
{{{x = (3 +- sqrt( -3^2-4*1*-28 ))/2 }}}
Multiply
{{{x = (3 +- sqrt(9+112 ))/2 }}}
Add
{{{x = (3 +- sqrt(121))/2 }}}
Split into 2 equations
{{{x = (3+11)/2 }}} OR {{{x = (3-11)/2 }}}
Add
{{{x=14/2}}} OR {{{x=-12/2}}}
Divide
{{{x=7}}} OR {{{x=-6}}}
<h3>7 or -6</h3>