Question 864804
This is not a right triangle because {{{25^2+23^2=1154<>900}}}.


Let q = measure of angle for vertex of the 23 ft. side with the 30 ft. side.
The 25 ft. side is opposite of angle with measure q.


Law of Cosines
{{{23^2+30^2-2*23*30*cos(q)=25^2}}}
{{{-2*23*30*cos(q)=25^2-23^2-30^2}}}
{{{cos(q)=(20^2+23^2-25^2)/(2*23*30)}}}
{{{cos(q)=304/(2*23*30)}}}
{{{152/(23*30)}}}
{{{76/(23*15)}}}
{{{highlight_green(cos(q)=76/345)}}}----something seems not right about this---
{{{highlight_green(q=77.2739)}}} degrees.


The height of this triangle, using base of 30 feet, is {{{23*sin(77.2739)}}}.
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Area, {{{highlight(highlight(A=(1/2)30*23*sin(77.2739)))}}}, which you need to simplify, and you will want to round to the nearest square foot, or maybe to the nearest tenth of a square foot.