Question 864874
{{{1/b + 1/(b - 4) = (b -3)/(b - 4)}}}

multiply equation by b(b-4)

{{{(b-4)+b=b(b-3)}}}


{{{b-4+b=b^2-3b}}}

2b-4=b^2-3b

b^2-5b+4=0

b^2-4b-b+4=0

b(b-4)-1(b-4)=0

(b-1)(b-4)=0

b=1