Question 864826
write the standard form of the equation of the parabola with its vertex at (0,0) and directrix y=-3/2.
given data shows that parabola opens up. (directrix is below the vertex of the parabola)
Its basic equation: (x-h)^2=4p(y-k), (h,k)=coordinates of vertex
since vertex is at the origin, basic equation is x^2=4py
For given parabola, p=3/2 (distance from vertex to directrix (and focus) on the axis of symmetry)
4p=6
Standard form of the equation for given parabola: x^2=6y