Question 864798
The median of a sorted (in increasing order) list of numbers is the middle number in the list. If the number of numbers is even, the median is defined as the average of the middle two. e.g. the median of {2,8,7,5,1} is 5 because {2,8,7,5,1} sorted in increasing order is {1,2,5,7,8}, and the median of {1,2,3,4,5,6} is 3.5.


The standard deviation *[tex \large \sigma]of a list of numbers *[tex \large x_1, x_2, \ldots, x_n] with mean *[tex \large \mu = \frac{\sum_{i=1}^n x_i}{n}] is defined as


*[tex \large \sigma = \sqrt{ \frac{\sum_{i=1}^n (x_i - \mu)^2}{n}} = \sqrt{ \frac{(x_1 - \mu)^2 + (x_2 - \mu)^2 + \ldots + (x_n - \mu)^2}{n}]


In other words, the variance (*[tex \large \sigma^2]) gives the mean of the square of the distances away from the mean. Since you have a large set of numbers, it'll be better done with a calculator.