Question 72887
{{{x^2-8x+3=0}}}
{{{x^2-8x=-3}}}
{{{x^2-8x+16=-3+16}}}
{{{x^2-8x+16=13}}}
{{{(x-4)^2=13}}}
We can write the last equation like this:
{{{(x-4)=sqrt(13)}}} 
{{{x=4+sqrt(13)}}} 
or
{{{(x-4)=-sqrt(13)}}}
{{{x=4-sqrt(13)}}}

So, solutions for this quadratic equations are:
{{{x=4+sqrt(13)}}} or {{{x=4-sqrt(13)}}} 

OK