<PRE><B>Question 864224</B>
Vector J has a magnitude of 28 ft and a direction of 
34 degrees west of north = 90+34 = 124 degrees
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Vector K has a magnitude of 48 ft and a direction of 
20 degrees south of east. = 340 degrees 
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Find the magnitude and direction of their sum.
x-coordinate:: 28cos(124) + 48cos(340) = 29.45
y-coordinate:: 28sin(124) + 48sin(340) = 6.80
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Ans:
Magnitude:: sqrt[29.45^2+6.80^2] = 30 ft
angle:: arctan(6.80/29.45) = 13 degrees
Ans: a
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a) 30 ft and 13 degrees north of east 
b) 36 ft and 54 degrees north of east 
c) 38 ft and 27 degrees south of west 
d) 40 ft and 14 degrees south of west
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