Question 864476
Points on the x-axis would have the form (x,0).
Use the distance formula,
{{{5^2=(x-5)^2+(0-4)^2}}}
{{{25=(x-5)^2+16}}}
{{{(x-5)^2=9}}}
{{{x-5=3}}} and {{{x-5=-3}}}
{{{x=8}}} and {{{x=2}}}
(8,0) and (2,0)