Question 864318
let the integers be x x+2 & x+4

x+x+2+x+4 = (x+2)(x+4)-42

3x+6=x^2+6x+8-42

3x+6 =x^2+6x-40

x^2+3x-40=0

x^2+8x-5x-40=0

x(x+8)-5(x+8)=0

(x+8)(x-5)=0

x=-8 OR x=5

but odd integer
so, x=5
5,7,9