Question 864206
(B) First do part (A) and use the p and q values in the function.


(A)  Those points give you:
{{{(-3)^2-3p+q=0}}} and {{{2^2+2p+q=5}}}
which is the system
{{{9-3p+q=0}}} and {{{4+2p+q=5}}}

{{{-3p+q=-9}}} amd {{{2p+q=1}}}

SYSTEM:
{{{highlight(3p-q=9)}}}
{{{highlight(2p+q=1)}}}


ELIMINATION METHOD is most convenient.
{{{5p=10}}}
{{{highlight(p=2)}}} from that find {{{highlight(q=-3)}}}


Function is {{{highlight(f(x)=x^2+2x-3)}}}, which you can evaluate for {{{f(x)=t-1}}} and {{{x=t}}}, and solve to find t.