Question 864178
How many ounces of a 15% alcohol solution and a 26% alcohol solution must be combined to obtain 33 ounces of a 19% solution?
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let x=amt of 15% alcohol to be used
33-x=amt of 26% alcohol to be used
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15%x+26%(33-x)=19%*33
.15x+8.58-.26x=6.27
.11x=2.31
x=21
33-x=12
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amt of 15% alcohol to be used=21 ounces
amt of 26% alcohol to be used=12 ounces