<PRE><B>Question 864115</B>
The two  bicyclists were 300 miles apart at 3 p.m. and were headed toward each other. If they met at 9 p.m. and one was traveling 20 miles per hour faster than the other, what was the speed of each bicyclist?      Can you include the rates and time of the problem please.
 both  cyclist in opposite side 
let speed of one cyclist is x m/h
other speed is     x+20 m/h
relative speed = x+x+20= 2 x+20 m/h
distance is 300 mile 
time taken =9-3=6 hours 
speed =distance/time
2 x +20 =300/6
2x+20=50
2x=30
x=15 m/h 
other speed will be x+20=15+20=35 m/h

Answer   15 and 35 m/h</PRE>