Question 864061
{{{8x+9/x=27}}} Yes, good work
 |Multiplying thru by 10x so as all denominators = 1
 8x^2 - 27x + 9 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (27 +- sqrt( 441 ))/(16) }}}
{{{x = (27 +- 21)/(16) }}}
x = 3   0r x = 3/8