Question 72834
Count how many "jumps" are needed to take the decimal from its current location to right after the 1st number that's not zero (which is 2). In this case the decimal moves 7 spots to the right to get 2.4. To write in scientific notation you need to write it as
{{{2.4*10^(-7)}}} 
This is written as such to get back to 0.00000024. You have to multiply 2.4 by a really small number to get a small number (anything to a negative power is a fraction. Eg {{{10^(-2)=1/100=.01}}})