Question 72789
How do you graph 6y+x Greater than or equal to a number...I just use that problem if you have to use another problem..
:
Let's use this equation"
3y + 6x >= 12
:
We want it in the general form (y=) in order to plot the coordinates in the
 graph.
Subtract 6x from both sides and you have:
3y >= -6x + 12
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We want y to have a coefficient of 1, divide equation by 3 and you have:
y >= -2x + 4
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Ignore the inequality signs for a minute and chose some values for x and find y
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Lets plot from -3 to + 3.  Since this is a straight line you really only need
 two but will make a table from -3 to 3 give you an idea of what's going on:
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Start with x = -3, find y
Substitute -3 for x in the equation y = -2x + 4
y = -2(-3) + 4
y = +6 + 4 
y = 10 when x = -3
:
Do the same for each value for x, the table should look like this:
 x | y
-------
-3 | 10
-2 | 8
-1 | 6
 0 | 4
+1 | 2
+3 | -2

plot each of these values on standard x/y graph paper, 
your graph should look like this:
{{{ graph( 300, 200, -10, 10, -10, 10, -2x + 4) }}}
:
Remember its y >= -2x + 4 so there is not a unique solution, but an
"area of feasibility". As you look at the graph, this area would be
at the line (=) and above the line ">". On this graph it would be 
the area above and to the right of the line'
:
:
Did this make sense to you, any questions.