Question 863733
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Hi
{{{15sqrt(6)sqrt(5)/3sqrt(5)sqrt(5) = 15sqrt(30)/15 = sqrt(30)}}}
{{{a^0 = 1}}}
{{{(a^p)^q = a^(p*q)}}}
{{{root(a,p)*root(a,q) = root(a,p*q)}}}  Applied
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}
{{{root(n, (x/y)) = root(n,x)/root(n,y)}}}
{{{(xy)^n = x^n*y^n}}}
{{{x^(1/n) = root(n,x)}}}   , {{{x^(m/n) = (root(n,x))^m}}}