Question 863696
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Hi
a) level of significance is .05
b) sample test statistic is 2.13  (degree of Freedom is 15
c) t = {{{(19.4-18.4)/(4/sqrt(36))}}} = 1.5,   P(t &#8804; 1.5) = .9228
  92.28 % chance the sample mean is &#8804; 19.4