Question 863573
{{{f(x)=a(x-2)(x+3)(x-5)}}}
{{{f(3)=a(3-2)(3+3)(3-5)=6}}}
{{{a(1)(6)(-2)=6}}}
{{{a=-1/2}}}
{{{f(x)=-(1/2)(x-2)(x+3)(x-5)}}}