Question 863416
{{{drawing(400,1200/7,-7,7,-3,3,

circle(5.65685425,0,0.11),circle(5.65685425,0,0.07),circle(5.65685425,0,0.05),circle(5.65685425,0,0.03),circle(5.65685425,0,0.01),

circle(-5.65685425,0,0.11),circle(-5.65685425,0,0.07),circle(-5.65685425,0,0.05),circle(-5.65685425,0,0.03),circle(-5.65685425,0,0.01),


arc(0,0,12,4)  )}}}
<pre>
Draw in an xy-coordinate system with the origin at the center:

{{{drawing(400,1200/7,-7,7,-3,3,

circle(5.65685425,0,0.13),circle(5.65685425,0,0.07),circle(5.65685425,0,0.05),circle(5.65685425,0,0.03),circle(5.65685425,0,0.01),
grid(1),
circle(-5.65685425,0,0.11),circle(-5.65685425,0,0.07),circle(-5.65685425,0,0.05),circle(-5.65685425,0,0.03),circle(-5.65685425,0,0.01),


arc(0,0,12,4)  )}}}

The distance from the center to the vertex = a = {{{1/2}}} the distance 
between the vertices = {{{1/2}}} the length of the major axis = {{{(1/2)*""}}}12m = 6m

The distance from the center to the covertex = b = {{{1/2}}} the distance 
between the covertices = {{{1/2}}} the length of the minor axis = {{{(1/2)*""}}}4m = 2m

c = the distance between the center and a focus.  
So the distance between the foci is 2c



For any ellipse,

c² = a² - b²
c² = 6² - 2²
c² = 36 - 4
c² = 32
 c = &#8730;<span style="text-decoration: overline">32</span>
 c = &#8730;<span style="text-decoration: overline">16·2</span>
 c = 4·&#8730;<span style="text-decoration: overline">2</span>

So 2c = 2(4·&#8730;<span style="text-decoration: overline">2</span>) = 8·&#8730;<span style="text-decoration: overline">2</span> m.

2c = 8·(1.732) = 11.3 meters approximately  

Edwin</pre>