Question 863423
Find the following probabilities for the following standard normal random variable Z. 
P (-2.22 < Z < 1.31) = normalcdf(-2.22,1.32) = 0.8917
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Another problem is: Suppose X is normally distributed random variable with mean=10 and SD=2 Find each of the following probabilities. 
A) P(10.56 less or equal X less or equal 14.7)
z(10.56) = (10.56-10)/2 =  0.28
z(14.7) = (14.7-10)/2 =  2.35
Then P(10.56<= x <=14.7) = P(0.28<= z <=2.35) = 0.3804
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B) P(5.28 less or equal X less or equal 12.7)
I'll leave that to you.
Cheers,
Stan H.