Question 72753
<pre>

If the problem is ³{{{sqrt(x^2)}}} = 4 or the cube root of x^2 = 4

        
                  ³{{{sqrt(x^2)}}}³ = 4³    let us undo cube root 
                                x^2 = 64    extract the sqrt
                           sqrt x^2 = sqrt 64
                                  x = 8
 

Checking : x = 8

      ³{{{sqrt(8^2)}}} = 4  
       ³{{{sqrt(64)}}} = 4
    ³{{{sqrt(4*4*4)}}} = 4
                     4 = 4 ----------->>True 


Therefore x = 4