Question 863371
{{{1/2x-2/3y=22}}}
{{{6(1/2)x-6(2/3)y=6(22)}}}
1.{{{3x-4y=132}}}
.
.
{{{4(1/2)x+4(1/4)y=0}}}
2.{{{2x+y=0}}}
From eq. 2,
{{{y=-2x}}}
Substitute into eq. 1,
{{{3x-4(-2x)=132}}}
{{{3x+8x=132}}}
{{{11x=132}}}
{{{x=12}}}
Then from eq. 2,
{{{y=-2(12)}}}
{{{y=-24}}}