Question 72708
Given:
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{{{f(x) = abs(x-3) - 4}}}
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Just pick some convenient values of x and solve for f(that value).  For example let's set
x at 0.  The equation becomes:
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{{{f(0) = abs(0-3) - 4 = abs(-3) - 4 = +3 -4 = -1}}}
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If you need this in the form of an (x,y) point, then this answer is (0,-1).
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Let's do it again. Set x = -5 to get:
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{{{f(-5) = abs(-5-3) - 4 = abs(-8) - 4 = +8 -4 = +4}}}
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and in the form of an (x,y) point, this answer is (-5,+4).
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And finally a 3rd point.  Set x = +6 and the equation becomes:
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{{{f(6) = abs(6-3) - 4 = abs(3) - 4 = +3 -4 = -1}}}
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and in point form this is (6,-1).
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You can try other values, but hopefully this will give you the idea of finding points on
the graph of f(x) by just assuming values of x and calculating corresponding values for
f(x) or y.