Question 863271
The sum of n consecutive odd integers is given by the following formula
Sn = (n/2)(2x1 + 2n - 2)  where x1 is the first integer in the sequence
in our example x1 is 1, therefore we have
10(4n+50) = (n/2)(2 +2n -2)
40n+500 = 2n^2 / 2
n^2 -40n -500 = 0
(n-50)(n+10) = 0
n is 50 or -10
in our case n = 50 is the required answer