Question 862955
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Hi
a)with  z = (344-183)/31 =  5.1935....
how many times would you expect there to be more passengers than available seats? never
b) $71000/$460 = 154
z = (154-183)/31 = - .9243  
P(z<-.9245) = 17.77%  of the time
c)  .1777*12 = 2.1324   Approximately  2 days 
my thoughts... 
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