Question 72735
Find the vertex of y=-2(x -3)^2 + 4 and then graph.

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There are several way to find the vertex.
You can rewrite the equation as y-4 = -2(x-3)^2
This follows the form y-k = a(x-h)^2
where (h,k) is the vertex.
So your vertex is at (3,4).
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To graph you could plot some points:
You know the x=3 is at the vertex, or on the axis of symmetry.
If x=4 you get y=-2*1+4 = 2; Point at (4,2) and by symmetry at (2,2)
If x=5 you get y=-2*5+4 = -6; Point at (5,-6) and by symmetry at (1,-6)
etc.
{{{graph(400,300,-10,10,-10,10,-2(x-3)^2+4)}}}
Cheers,
Stan H.