Question 862770
sum of four consecutive integers is 686, then what is the sum of four previous consecutive integers ?
:
Find the first of the 4 integers that add up to 686
n+(n+1)+(n+2)+(n+3) = 686
4n + 6 = 686
4n = 680
n = 680/4
n = 170 
then the previous four:
169+168+167+166 = 670