Question 861651
2log base 10 6 - 1/3log base 10 27 = log base 10 of x 
{{{2log(6)-(1/3)log(27)=log(x)}}}
{{{log(6^2)-log(27^(1/3))=log(x)}}}
27^(1/3)=3
{{{log(36)-log(3)=log(x)}}}
log(36/3)=log(x)
x=12