Question 862736
2log(x+1)-log(x-1)=log(x+4)
solve for x:
{{{2log((x+1))-log((x-1))=log((x+4))}}}
{{{log(((x+1)^2/(x-1)))=log((x+4))}}}
{{{(x+1)^2/(x-1)=(x+4)}}}
(x-1)^2=(x-1)(x+4)
x^2-2x+1=x^2+3x-4
x=5