Question 862667
<pre><font face = "consolas" color = "indigo" size = 3><b>
Hi
y+8+3x^2=12x 
 y = -3x^2 + 12x - 8   P(0,-8) and (1,1) on this parabola opening downward -3 < 0
Completing the Square
 y = -3(x-2)^2 + 12 - 8
 y = -3(x-2)^2 + 4   V(2,4) line of symmetry x = 2
{{{drawing(300,300,   -6, 6, -10, 6, grid(1), blue(line(2,6,2,-10)) ,
circle(0, -8,0.2),
circle(2, 4,0.2),
circle(1, 1,0.2),
graph( 300, 300, -6, 6, -10, 6, 0 ,-3x^2 + 12x -8  ) )}}}