Question 862564
Use the 1st principle to find the first derivative [f^'(x)] if
G(x)=cosec2x at x=pi/6
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You didn't give f(x)
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If you want G'(x)
G'(x) = -2csc(2x)*cot(2x)
G'(pi/6) = -2*(2/sqrt(3))*(1/sqrt(3))
= -4/3