Question 862601
Let N be the number,
{{{1/N=N-1}}}
{{{1=N^2-N}}}
{{{N^2-N-1=0}}}
Use the quadratic formula,
{{{N = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{N = (-(-1) +- sqrt( (-1)^2-4*1*(-1) ))/(2*1) }}}
 {{{N = (1 +- sqrt( 1+4 ))/(2) }}}
{{{N = (1 +- sqrt( 5 ))/(2) }}}
Since you only want the positive solution,
{{{N = (1 + sqrt(5 ))/(2) }}}