<PRE><B>Question 862374</B>
The point Q(-3,6) is on the terminal arm of an angle in standard position. Determine the value of that angle.
------
Q is in QII where x is negative and y is positive.
===
Ans: arctan(-6/3) = arctan(-2) = -63.43 degrees
---
Ans: Since the angle is in QII, angle = 180-63.43 = 116.57 degrees
======================================
Cheers,
Stan H.
================</PRE>