Question 862188
{{{(7-i)/(3-4i)=((7-i)/(3-4i))*((3+4i)/(3+4i))}}}
{{{(7-i)/(3-4i)=(21+28i-3i-4i^2)*(9+12i-12i-16i^2)}}}
{{{(7-i)/(3-4i)=((21+4)+25i)*(9+16)}}}
{{{(7-i)/(3-4i)=1+i}}}
{{{abs(1+i)=sqrt(1^2+1^2)=sqrt(2)}}}
{{{arg(1+I)=tan^(-1)(1/1)=pi/4}}}