<PRE><B>Question 862143</B>
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Take another look at your factoring of the original polynomial.  When you factor out *[tex \Large x\ -\ 5], you get *[tex \Large 2x^3\ +\ x^2\ + 4x\ +\ 2].  Try *[tex \Large 2x\ +\ 1] as your next factor...


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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